Question

Please help?

Answer 1

`"see explanation"`

Explanation:

`"since the triangles are all right triangles we can use basic"`
`color(blue)"trigonometric ratios "" to solve for "theta`

`"using h for hypotenuse, a for adjacent and o for opposite"`

`•color(white)(x)tantheta=o/a" and "costheta=a/h`

`(1)color(white)(x)costheta=a/h=12/13`

`rArrtheta=cos^-1(12/13)~~22.6^@`

`(2)color(white)(x)tantheta=o/a=4/13`

`rArrtheta=tan^-1(4/13)~~17.1^@`

`(3)color(white)(x)costheta=a/h=6/9`

`rArrtheta=cos^-1(6/9)~~48.2^@`

`(4)color(white)(x)tantheta=o/a=11.9/10`

`rArrtheta=tan^-1(1.19)~~50.0^@`