Question

Please help me find the functions?

Answer 1

1. -99
2. `x^2-37x+6`
3. -4
4. `6-x-36sqrtx`

Explanation:

`g(k(9))=g(sqrt9)=g(3)=g(3^2-36xx3)=-99`

`(g+h)(x)=(x^2-36x+6-x)(x)=x^2-37x+6`

`g[f(2^{-2})]=g[-1/(2^{-2})]=-g[-1/(1/4)]=-4`

`h(g(k(x)))=h(g(sqrtx)))=h((sqrtx)^2-36sqrtx)`

`=h(x-36sqrtx)=6-x-36sqrtx`