# Please help with?

##### 2 Answers

Event A:

Event B:

#### Explanation:

Event A: Their sum is greater than 7

We can solve through complementary events.

P(sum greater than 7) = 1- P(sum equal to 7)

What are the numbers that equal to 7?

1,6

2,5

3,4

4,3

5,2

6,1

In each case, you have

Looking at 1,6

You have

The

Therefore, P(sum equal to 7) =

So, P(sum greater than 7) =

Event B: the sum is not divisible by 4 and not divisible by 6

The largest sum you can have between two numbers is 12 ie 6+6 and the smallest number you can have is 2 ie 1+1

So numbers divisible by 4 in that range are: 4, 8, 12

and numbers divisible by 6 in that range are: 6, 12

Therefore, looking at the table below, you can see that there are 14 combinations that you cannot throw. Since each combination ie 1,3 or 6,6 and you have

P(sum not divisible by 4 and 6) = 1-P(sum is divisible by 4 and 6)

P(sum not divisible by 4 and 6) =

![https://useruploads.socratic.org/Fg5eZ6JsQ8GC11vrgJ6g_sum_of_2_dice.jpg)

#### Explanation:

Consider all the possible results of two dice rolls.

In total, there are

Therefore,