Given: a rectangle #ABCD, /_ C# is trisected by #CF# and #CE#, where #E# is on #bar(AB), F# is on #bar(AD), BE = 6, AF = 2#.
Find area of rectangle.
Trisected means that #/_C = 90^@# is cut evenly into three angles.
#90/3 = 30^@#
Use trigonometry to first find #BC#:
#(tan 30^@)/1 = 6/(BC); " "BC = 6/(tan 30^@) ~~10.39 " units" #
Since #AD = BC#, calculate #FD#:
#FD = 10.39 - 2 = 8.39 " units" #
Use trigonometry to first find #DC#:
#(tan 30^@)/1 = (FD)/(DC); " "DC = 8.39/(tan 30^@)~~14.5 " units"#
Area #= (BC) * (DC) ~~ 10.39 * 14.5 ~~150.7 " units"^2#
Answer #4#