Please solve the q 1 ?

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Answer 1 · 2018-04-27T11:54:23

The answer is # option (4)#

The reaction is

#Z_2O_3 +3H_2 rarr2Z+3H_2O #

#0.006 g# of hydrogen is required for the reduction of #0.1596g # of oxide

#6g# of hydrogen will reduce

#=0.1596*6/0.006=159.6g# of oxide

Therefore,

#2M_Z+M_(3O)=159.6#

#2M_Z+3*16=159.6#

#2M_Z=159.6-48=111.6#

#M_Z=111.6/2=55.8g#

The answer is # option (4)#