Plz help Solve for x?

#dy/dx=2/sqrt(4x-7)-2/3#

1 Answer
Jan 19, 2018

#x = 36/(4(3(dy/dx)+2)^2) + 7/4#

Explanation:

I am assuming thaty you want to solve for #x# in terms of #dy/dx# rather than in terms of #dy# and #dx#.

#dy/dx=2/sqrt(4x-7)-2/3#

Replace #dy/dx# by #D# to simplify notation until the end.

#D = 2/sqrt(4x-7)-2/3#

#3Dsqrt(4x-7) = 6 -2sqrt(4x-7)#

#3Dsqrt(4x-7) + 2sqrt(4x-7) = 6 #

#(3D+2)sqrt(4x-7) = 6#

#sqrt(4x-7) = 6/(3D+2)#

#4x-7 = 36/(3D+2)^2#

#4x = 36/(3D+2)^2 + 7#

#x = 36/(4(3D+2)^2) + 7/4#

#x = 36/(4(3(dy/dx)+2)^2) + 7/4#