# Point A is at #(3 ,-2 )# and point B is at #(5 ,-4 )#. Point A is rotated #(3pi)/2 # clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

##### 1 Answer

(2 , 3) , ≈ 4.79

#### Explanation:

Under a rotation of

#(3pi)/2" clockwise about the origin " # a point (x , y) → (-y , x )

hence A (3 , -2) → A' (2 , 3 )

To find the change in distance , requires to calculate the length of AB and A'B , and subtract them to find the change.

We can calculate the lengths using the

#color(blue)" distance formula " #

#color(red)(|bar(ul(color(white)(a/a)color(black)( d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2))color(white)(a/a)|)))#

where# (x_1,y_1)" and " (x_2,y_2)" are 2 coordinate points "# For length AB let

# (x_1,y_1)=(3,-2)" and " (x_2,y_2)=(5,-4)#

# d_(AB) = sqrt((5-3)^2 + (-4+2)^2)=sqrt(4+4) ≈ 2.83# For A'B let

# (x_1,y_1)=(2,3)" and " (x_2,y_2)=(5,-4)#

# d_(A'B) = sqrt((5-2)^2 + (-4-3)^2)=sqrt(9+49) ≈ 7.62 # hence , change in length = 7.62 - 2.83 = 4.79