Question

Privé that (1+cosx)/sinx=sinx/(1-cosx)?

Answer 1

`"see explanation"`

Explanation:

`"using the "color(blue)"trigonometric identity"`

`•color(white)(x)sin^2x+cos^2x=1`

`rArrsin^2x=1-cos^2x`

`"consider the left side"`

`"multiply numerator/denominator by "(1-cosx)`

`rArr((1+cosx)(1-cosx))/(sinx(1-cosx))`

`=(1-cos^2x)/(sinx(1-cosx))`

`=(cancel(sinx)sinx)/(cancel(sinx)(1-cosx))`

`=sinx/(1-cosx)=" right side "rArr"verified"`