1

# Prove that lines BD, FX and ME are concurrent?

## Triangle BCF has a right angle at B. Let A be the point on line CF such that FA=FB and F lies between A & C. Point D is chosen such that DA =DC and AC is the bisector of $\angle$ DAB. Point E is chosen such that EA=ED and AD is the bisector of $\angle$EAC. Let M be the midpoint of CF. Let X be the point such that AMXE is a parallelogram. Prove that lines BD, FX and ME are concurrent.

preview ×
• Edit wording or topic
Update the question or its topic
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Write a one sentence answer...

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer
##### Just asked! See more
• 7 minutes ago
• 8 minutes ago
• 10 minutes ago
• 11 minutes ago
• 36 seconds ago
• A minute ago
• 2 minutes ago
• 3 minutes ago
• 4 minutes ago
• 6 minutes ago
• 7 minutes ago
• 8 minutes ago
• 10 minutes ago
• 11 minutes ago