Prove that #P(barA//B) = 1-P(A//B)#?

1 Answer
Cesareo R.
Feb 16, 2018

See below.

Explanation:

#P(A|B) = (P(A nn B))/(P(B))#
#P(barA | B) = (P(barA nn B))/(P(B))# then

#P(A|B)+P(barA | B) =(P(A nn B))/(P(B))+ (P(barA nn B))/(P(B)) = #

#= (P(A nn B)+ P(barA nn B))/(P(B)) = (P(B))/(P(B)) = 1#

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