Prove that sin square A + sin square A - tan square A = tan square A ??

1 Answer
May 5, 2018

#sin ^2 A+ sin ^2 A - tan ^2 A = tan ^2 A# is equivalent to #sin^2 A = tan^2 A#. Unfortunately it
isn't true, as # A=45^circ# provides an easy counterexample.

Explanation:

That says show

#sin ^2 A+ sin ^2 A - tan ^2 A = tan ^2 A#

That can't possibly be true. Let's try #A=45^circ#

# (1/sqrt{2})^2 + (1/sqrt{2})^2 - 1^2 = 1/2 + 1/2 -1 = 0 #

That's not equal to #tan^2 A = 1#.