Prove the identity?

#(6tanθ)/(1+tan^2θ)=3sin2θ#

Thank yall

1 Answer
Narad T.
Dec 3, 2017

See the proof below

Explanation:

We need

#tantheta=sintheta/costheta#

#1+tan^2theta=sec^2theta#

#sin2theta=2sinthetacostheta#

Therefore,

#LHS=(6tantheta)/(1+tan^2theta)#

#=(6sintheta/costheta)/(sec^2theta)#

#=(6sintheta)/costheta*cos^2theta#

#=6sinthetacostheta#

#=3sin(2theta)#

#=RHS#

#QED#

Related questions
Impact of this question
642 views around the world
You can reuse this answer
Creative Commons License