Prove the identity sinx=cos(pi/2-x)?

1 Answer
Apr 29, 2018

#"see explanation"#

Explanation:

#"using the "color(blue)"trigonometric identity"#

#•color(white)(x)cos(a-b)=cosacosb+sinasinb#

#"here "a=pi/2" and "b=x#

#rArrcos(pi/2-x)#

#=cos(pi/2)cosx+sin(pi/2)sinx#

#=(0xxcosx)+(1xxsinx)=sinx#