Prove the identity sinx=cos(pi/2-x)?
1 Answer
Apr 29, 2018
Explanation:
#"using the "color(blue)"trigonometric identity"#
#•color(white)(x)cos(a-b)=cosacosb+sinasinb#
#"here "a=pi/2" and "b=x#
#rArrcos(pi/2-x)#
#=cos(pi/2)cosx+sin(pi/2)sinx#
#=(0xxcosx)+(1xxsinx)=sinx#