Question 21?
2 Answers
Mar 6, 2018
Explanation:
For a stationary point,
now,
or,
Mar 6, 2018
Explanation:
#"to find the x-coordinate of a stationary point"#
#"differentiate and equate to zero"#
#g(x)=9x^3-36x+35larr" differentiate using power rule"#
#rArrg'(x)=27x^2-36#
#"for stationary points let "g'(x)=0#
#rArr27x^2-36=0#
#rArr9(3x^2-4)=0#
#rArr3x^2=0+4=4#
#rArrx^2=4/3#
#color(blue)"take the square root of both sides"#
#rArrx=+-sqrt(4/3)=+-sqrt4/sqrt3=+-2/sqrt3#
#"the required x-coordinate is "x=2/sqrt3toB#