Ratio of Cp and Cv of a gas 'X' is 1.4. Calculate the number of atoms of the gas present in 11.2 liters of it at NTP?
There are 5.61 × 10²³ atoms in the gas.
You know that
You also know that
A monatomic gas has three translational degrees of freedom (
A diatomic gas has three translational and two rotational degrees of freedom
So the gas is diatomic and has the formula X₂.
Now, according to the Ideal Gas Law,
No. of atoms = 0.4563 mol X₂ ×