Question

Resistance?

`1.) In this problem, you will calculate the basic quantities in a simple electric circuit.
A 83 Ω resistor and a length of wire of resistance 18 Ω are connected in series across a 57 V power supply.
Calculate the current flowing in the circuit.
Give your answer in Amps

2.) Calculate the power dissipated in the 83 Ω resistor..
Give the answer in Watts.

Answer 1

1.) `I = 0.56" A"`

2.) `P = 26.4" W"`

Explanation:

The total resistance of the circuit is:

`R_"total" = 83" "Omega+18" "Omega`

`R_"total" = 101" "Omega`

The current in the circuit is the source voltage divided by the total resistance:

`I = V/R_"total"`

`I = (57" V")/(101" "Omega)`

`I = 0.564" A"`

The power dissipated by the resistor is the square of the current through it multiplied by the resistance of the resistor:

`P = I^2R`

`P = (0.564" A")^2(83" "Omega)`

`P = 26.4" W"`