#### Explanation:

We are given that car consumes 6 $l$ of gas every 100 $k m$.

$\therefore$ In 2000 $k m$ car will consume : $\left(\frac{6}{100} \times 2000\right)$ $l$ of gas.

$\therefore \frac{6}{\cancel{100}} \times 20 \cancel{00}$ $=$ $6 \times 20 = 120$ $l$ of gas.

Now, 1 $l$ gas costs : $1.20 $\therefore$120 $l$gas would cost : (1.20 xx 120)$

#= $144 $\therefore$Sathish would have to pay$144 at the end of the road-trip for gas.