(secx-cosx)^2?
1 Answer
Mar 7, 2018
We rewrite entirely in terms of cosine:
#=(1/cosx - cosx)^2#
#=((1 -cos^2x)/cosx)^2#
#=((sin^2x)/cosx)^2#
#=sin^4x/cos^2x#
#=sin^2x/cos^2x sin^2x#
#=tan^2xsin^2x#
Hopefully this helps!