Show that?

Question

300 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-19T15:46:31

Given

#(1+4x^2)cosA=4x#

#=>1/cosA=(1+4x^2)/(4x)#

By componendo and dividendeno we get

#(1+cosA)/(1-cosA)=(1+4x^2+4x)/(1+4x^2-4x)#

#=>(1+cosA)^2/(1-cos^2A)=(1+2x)^2/(1-2x)^2#

#=>(1+cosA)^2/sin^2A=(1+2x)^2/(1-2x)^2#

#=>(1+cosA)/sinA=(1+2x)/(1-2x)#

#=>1/sinA+cosA/sinA=(1+2x)/(1-2x)#

#=>cscA+cotA=(1+2x)/(1-2x)#