Question

Show that Log _a_b=1/log_b_a ?

Answer 1

See below

Explanation:

Im presuming that you mean `Log (a/b) = 1/Log(b/a)` .
Well, in this case treat it the same as diving any fractions. To get rid of the denominator you must multiply both the numerator and the denominator by the same value as the denominator. Remember that everytime you divide by a fraction, its basically the same as multiplying the flipped version of it So, `1/log(b/a)` is the same as `1 ⋅ Log(a/b)` and thats just `Log(a/b)`, thus proving that `Log (a/b) = to 1/Log(b/a)`.