Simplify 10i^3+6i^13-12i^10???? express d following in a+bi 1.5 2.-3i 3.0

1 Answer
Apr 18, 2018

It depends on whether your 'i' is #sqrt(-1)# or just a variable.

Explanation:

For #i = sqrt(-1)# the expression simplifies to:

#-10i - 6i + 12# because every 2 'i' exponents is -1.
Final form: #-16i + 12#

The second part is not really making any sense to me as written.
Again, for #i = sqrt(-1)# the expressions would be:

#5 + 0i# ; #0 -3i#; and #0 + 0i#