Simplify #(csc^2Theta-3cscTheta+2)/(csc^2Theta-1)# ?

1 Answer
P dilip_k
May 1, 2018

#(csc^2theta-3csctheta+2)/(csc^2theta-1)#

#=(csc^2theta-csctheta-2csctheta+2)/((csctheta-1)(csctheta+1))#

#=(csctheta(csctheta-1)-2(csctheta-1))/((csctheta-1)(csctheta+1))#

#=((csctheta-1)(csctheta-2))/((csctheta-1)(csctheta+1))#

#=(csctheta-2)/(csctheta+1)#

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