Simplify #sec(Theta+pi)# ?

1 Answer
Noah G
Apr 8, 2018

#sec(theta + pi)= -sectheta#

Explanation:

Recall that #sectheta = 1/costheta# and #cos(A + B) = cosAcosB - sinAsinB#.

#sec(theta + pi) = 1/(costhetacospi - sinthetasinpi) = 1/(-costheta) = -sectheta#

Hopefully this helps!

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