Simultaneous equation ???

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Answer 1 · 2017-03-14T11:03:33

The solution of the system of linear equations:

${((1/2x+y) = 5),(x-2y=6):}$

is:

${(x=8),(y=1):}$

We have a system of linear equations in two unknowns:

${((1/2x+y) = 5),(x-2y=6):}$

We can solve it by substitution: from the second equation we have:

$x=6+2y$

Substituting this expression in the first equation we have:

$1/2(6+2y)+y = 5$

$3+y+y =5$

$2y= 5-3$

$2y=2$

$y=1$

and then:

$x=6+2 = 8$