Sin^26x-sin^24x=sin2x.sin10x?

1 Answer
Jane
Feb 24, 2018

Given, # sin ^2 6x - sin ^2 4x #

#= 1/2 (2 sin ^2 6x - 2 sin ^2 4x)#

# = 1/2 (1- cos 12x + cos 8x -1)# (using, #cos 2theta = 1- 2sin ^2 theta#)

#= - 1/2 [ cos(10x +2x) - cos (10x - 2x)]#

# = sin 10x 2x#

(using the formula of #sin a sin b = -1/2 [cos(a+b) - cos(a-b)]#)

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