Sin^2x+sin^2x cot^2x ?

2 Answers
Dec 13, 2017

1

Explanation:

sin^2x+sin^2x cot^2x

= sin^2x*(1+cos^2x/sin^2x)

= sin^2x*((sin^2x+cos^2x)/sin^2x)

= sin^2x*(1/sin^2x)

= sin^2x/sin^2x

= 1

Dec 13, 2017

See the answer below....

Explanation:

sin^2x+sin^2x cdot cot^2x
=sin^2x+sin^2x cdot cos^2x/sin^2x
=sin^2x+cancel(sin^2x) cdot cos^2x/cancel(sin^2x)
=sin^2x+cos^2x
=1 [As identity]