Question

Sin(3a)/sin(a)-cos(3a)/cos(a)=?

Answer 1

`Sin(3a)/sin(a)-cos(3a)/cos(a)`

`=(3Sina-4sin^3a)/sina-[(4cos^3a-3cosa)/cosa]`

`=3-4sin^2a-4cos^2a+3`

`=3+3-4(sin^2a+cos^2a)`

`=6-4(1) = 2`