#sin(3x+5)# find differentiate ?

1 Answer
Mar 12, 2018

#3cos(3x+5)#

Explanation:

What we have here is a composite function, and whenever we're taking the derivative of a composite function, it helps to use the Chain Rule.

#sin(3x+5)# is composed of the functions #sinx# and #3x+5#. I'll define the following:

  • #f(x)=sinx#
  • #g(x)=3x+5#

Given this, the Chain Rule tells us that the derivative of #sin(3x+5)# will be:

#f'(g(x))*g'(x)#

Let's differentiate #f# and #g#. We get:

  • #f'(x)=cosx#
  • #g'(x)=3#

Let's plug in! We get:

#cos(3x+5)*3#

Which can be rewritten as:

#3cos(3x+5)#