Slope of tangent to the circle #(x-r)^2 + y^2 = r^2# at the point #(x,y)# lying on the circle is?
A) #x/(y-r)#
B) #(r-x)/y#
C) #(y^2-x^2)/y#
D) #(y^2 + x^2)/(2xy)#
A)
B)
C)
D)
1 Answer
Oct 20, 2017
B)
Explanation:
Implicitly differentiate
This is selection B)