Sodium reaction with Iodine(1) chloride.What is equation?my answer was 2Na+2ICl》2NaCl+I2.But it is incorrect.Correct answer is 2Na+ICl》NaCl+NaI How?
1 Answer
Feb 25, 2018
Well, sodium is a strong reducing agent....and the halogens are oxidizing agents....and so are the INTERHALOGENS....
Explanation:
And so we take
In your answer you suggested that iodide anion was oxidized...which would be a hard thing to do in these reducing conditions....