Solve 8(10^y+4)=38−5(1−10^y)?

1 Answer
Dec 5, 2017

#y = log(1/3)#

Explanation:

Distribute:

#8*10^y+32=38-5+5*10^y#

Rearrange:

#3*10^y +32 = 33#

A little more rearranging:

#3*10^y=1#

#10^y=1/3#

Take the log of both sides in base 10:

#log(10^y) = log(1/3)#

Use the fact that log base 10 and 10^y are inverses:

#y = log(1/3)#