Solve cos 3theta+cos 2theta=sin 3theta/2+sin theta/2?

#cos 3theta+cos 2theta=sin {(3theta)/2}+sin {theta/2}#

1 Answer
May 26, 2018

#cos 3theta+cos 2theta=sin ((3theta)/2)+sin (theta/2)#

#=>2cos ((5theta)/2)cos (theta/2)=2sin thetacos (theta/2)#

#=>cos ((5theta)/2)cos (theta/2)-sin thetacos (theta/2)=0#

#=>cos(theta/2)(cos ((5theta)/2)-sin theta)=0#

When

#cos(theta/2)=0#

#=>theta/2=(2n+1)pi/2" where "n inZZ#

#=>theta=(2n+1)pi" where "n inZZ#

When #cos ((5theta)/2)-sin theta=0#

#=>cos ((5theta)/2)=cos(pi/2- theta)#

#=>(5theta)/2=2kpipm(pi/2- theta)" where "k in ZZ#

So #(5theta)/2=2kpi+(pi/2- theta)" where "k in ZZ#
#=>(7theta)/2=2kpi+pi/2" where "k in ZZ#

#=>theta=1/7(4k+1)pi" where "k in ZZ#

Again

#(5theta)/2=2kpi-(pi/2- theta)" where "k in ZZ#

#=>(5theta)/2=2kpi-pi/2+ theta" where "k in ZZ#

#=>(3theta)/2=(4k-1)pi/2" where "k in ZZ#

#=>theta=1/3(4k-1)pi" where "k in ZZ#