Solve cox X= square root 3/2 where 0 less than or equal to X less than an equal to pi2. a) how many solutions are possible? b) in which quadrants would you find the solutions?
1 Answer
Jan 3, 2018
Explanation:
#cosx=sqrt3/2#
#"since" cosx>0" then x is in first or fourth quadrants"#
#cosx=sqrt3/2rArrx=pi/6larrcolor(blue)"in first quadrant"#
#"or "x=(2pi-pi/6)=(11pi)/6larrcolor(blue)"in fourth quadrant"#
