Solve cox X= square root 3/2 where 0 less than or equal to X less than an equal to pi2. c) Determine the related angle for the equation? D) determine all the solutions for the equation?
1 Answer
Dec 19, 2017
Explanation:
#cosx =sqrt3/2#
#rArrx=cos^-1(sqrt3/2)=pi/6larrcolor(blue)"related acute angle"#
#"since "cosx>0" then x is in first/fourth quadrants"#
#rArrx=pi/6larrcolor(blue)"first quadrant"#
#rArrx=(2pi-pi/6)=(11pi)/6larrcolor(blue)"fourth quadrant"#
#x=pi/6" or "x=(11pi)/6to[0,2pi]#
