solve for x;5.012^x=10^2x-1?

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Answer 1 · 2018-03-01T17:03:50

#x~~0.7692373148#

Not sure if this is the right equation:

#5.012^x=10^(2x-1)#

Taking common logs of both sides:

#xlog_(10)(5.012)=(2x-1)log_(10)(10)#

#xlog_(10)(5.012)=2x-1#

#log_(10)(5.012)=2-1/x#

#x=(-1)/(log_(10)(5.012)-2)#

#x~~0.7692373148#