# Solve for #x#? #e^(2x)-5=ln(x)+7# Please and thank you!!

##### 1 Answer

#### Explanation:

I would solve this graphically, as algerbraically seems rather advanced. I would draw two graphs,

the values of x that solve the equation, have to be on both graphs, i.e. must be where the graphs cross each other.

We find that there are two solutions, A=(0, -4) and E=(1.25, 7.22)

Now, ln(0) is undefined, but we see that

x=0 inserted in g:

The other value is