Solve sin3x = cos3x for 0° < x < 360° ?

1 Answer
Narad T.
Apr 27, 2018

The solution is #S={1/4pi+k/3pi ;AA k in ZZ }#

Explanation:

The equation is

#sin(3x)=cos(3x)#

Therefore,

Dividing by #cos(3x)#

#sin(3x)/cos(3x)=1#

#tan(3x)=1#

#3x=pi/4+kpi#, #AA k in ZZ#

#x=1/4pi+k/3pi#, #AA k in ZZ#

graph{sin(3x)-cos(3x) [-1.34, 16.43, -4, 4.89]}

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