Solve the inequality #(y+4)/(1-y) > 0#?

1 Answer
Apr 14, 2018

The solution is #y in (-4,1)#

Explanation:

Let #f(y)=(y+4)/(1-y)#

Build a sign chart

#color(white)(aaaa)##y##color(white)(aaaa)##-oo##color(white)(aaaa)##-4##color(white)(aaaaaa)##1##color(white)(aaaaa)##+oo#

#color(white)(aaaa)##y+4##color(white)(aaaaaa)##-##color(white)(aaaa)##+##color(white)(aaaaa)##+##color(white)(aaaa)###

#color(white)(aaaa)##1-y##color(white)(aaaaaa)##+##color(white)(aaaa)##+##color(white)(aa)##||##color(white)(aa)##-#

#color(white)(aaaa)##f(y)##color(white)(aaaaaaa)##-##color(white)(aaaa)##+##color(white)(aa)##||##color(white)(aa)##-#

Therefore,

#f(y)>0# when #y in (-4,1)#

graph{(x+4)/(1-x) [-16.02, 16.02, -8.01, 8.01]}