Solve the quation 3sin x = 1 for 0° ≤ x ≤ 720° .?
1 Answer
May 13, 2018
Explanation:
#"divide both sides by 3"#
#rArrsinx=1/3#
#rArrx=sin^-1(1/3)=19.5^@" to 1 dec. place"#
#"since "0<= x<=720"#
#"we have to go round the unit circle twice"#
#rArrx=(180-19.5)^@=160.5^@#
#rArrx=(360+19.5)^@=379.5^@#
#rArrx=(540-19.5)^@=520.5^@#