Solve the quation 3sin x = 1 for 0° ≤ x ≤ 720° .?

1 Answer
May 13, 2018

#x=19.5^@,160.5^@,379.5^@,520.5^@#

Explanation:

#"divide both sides by 3"#

#rArrsinx=1/3#

#rArrx=sin^-1(1/3)=19.5^@" to 1 dec. place"#

#"since "0<= x<=720"#

#"we have to go round the unit circle twice"#

#rArrx=(180-19.5)^@=160.5^@#

#rArrx=(360+19.5)^@=379.5^@#

#rArrx=(540-19.5)^@=520.5^@#