Question

Solve xy^1+4y=x³y²?

Answer 1

`y=(x+4)/x^3,x!=0`

Explanation:

`xy^1+4y=x^3y^2`

Factor `y` out of the left side.
`y(x+4)=x^3y^2`

Isolate for `y`.
`(x+4)/x^3=(y^2)/y`

`y=(x+4)/x^3,x!=0`

Note: since this is a rational expression, don't forget to state restrictions to variables in the denominator.