# Space vehicles use solid lithium hydroxide to remove exhaled carbon dioxide according to the equation: 2LiOH+CO_2 ->Li_2CO_3+H_2O. What is the mass of carbon dioxide removed if the space vehicle carries 42.0 mol LiOH?

The reaction stoichiometry clearly indicates that $21.0$ $\text{mol}$ $C {O}_{2}$ can be removed. This represents approx. $1$ $k g$ of carbon dioxide.
Mass of carbon dioxide removed: $=$ $21 \cdot \cancel{m o l} \times 44.0 \cdot g \cdot \cancel{m o {l}^{-} 1}$ $=$ ?? $g$