# Spinning a wheel, the probability of landing in area A is .99 probability of landing in area B is .01. In 60 spins what is the probability of landing in area B?

##### 2 Answers

Probability = 0.6%

#### Explanation:

First we convert the probability of Area B from dec

To find the probability of landing in Area B, we multiply the probability of area B by the number of spins, so it looks like

I hope that helped!

#### Explanation:

There are only two possible sets of outcomes:

#"all 60 spins land on A"#

#"at least one spin lands on B"#

Therefore, we can say that:

#P("all 60 A") + P("at least 1 B") = 1#

So in order to find the chance of at least 1 spin landing on B, let's first find the chance that all 60 spins land on A:

#P("all 60 A") = underbrace(P(A)timesP(A)times cdots timesP(A))_(60 color(white)"." "times") = (P(A))^60#

#=0.99^60 ~~ 0.5472#

Therefore:

#P("all 60 A") + P("at least 1 B") = 1#

#0.5472 + P("at least 1 B") = 1#

#P("at least 1 B") = 0.4528#

*Final Answer*