# Suppose a force of 100 newtons is used to push an object a distance of 5 meters in 15 seconds. Find the work done and the power for this situation

Feb 1, 2015

The answers are: $L = 500 J \mathmr{and} P = 33.3 W$.

To answer to the questions these formulae are needed:

$L = \vec{F} \cdot \vec{s}$: where the $\cdot$ is the scalar product;

and:

$P = \frac{L}{t}$

So:

$L = 100 N \cdot 5 m = 500 J$

(I supposed that the angle between $F \mathmr{and} S$ is 0);

and:

$P = \frac{500 J}{15 s} = 33.3 W$.