# Suppose a treadmill has an average acceleration of 4.7 * 10^-3 m/s^2. How much does its speed change after 5.0 min? If the treadmill's initial speed is 1.7 m/s, what will its final speed be?

Jan 24, 2017

Final velocity =3.11m/s

#### Explanation:

First of all lets see what is given

$a = 4.7 \cdot {10}^{-} 3$$\frac{m}{s} ^ 2$=$0.0047 \frac{m}{s} ^ 2$
$t = 5 \min = 5 \cdot 60 = 300 s$
$u = 1.7 \frac{m}{s}$
v=?

Remember its a tip that if you write this given part so systematically its really not a waste of TIME.

now ,by this part we can easily choose the formula

$a = \frac{v - u}{t}$
$0.0047 = \frac{v - 1.7}{300}$
$1.41 = v - 1.7$
$v = 3.11 \frac{m}{s}$