Suppose an iron ball weighing 10 N were dropped from a height of 10 m from the ground, what would be the change in temperature of the ball? Assume that no heat was lost to the surroundings. (Specific heat of iron = 0.42 J/g°C).

1 Answer
A08
Feb 16, 2018

When iron ball is dropped from a height of #10\ m# from the ground, it looses it Gravitational Potential Energy which gets converted to its kinetic energy. As the ball hits the ground, all the kinetic energy is to treated to be used in heating the iron ball.

Heat energy available to increase the temperature of ball #=mgh#
#=10xx10=100\ J#
Taking #g=10\ ms^-2#, mass of ball #=10/10=1\ kg#

We know that heat absorbed #Q=msDeltaT#
Inserting various values in SI units we get

#100=1xx(0.42xx1000)xxDeltaT#
#=>DeltaT=100/(0.42xx1000)=0.24\ C " degrees"#

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