Question

Suppose `sin(x) = 9/11` and that #90 < x < 180, how do you find cos(x) and tan (x)?

Answer 1

`sin x = 9/11 = 0.82`

`cos^2 x = 1 - sin^2 x = 1 - 0.67 = 0.33 -> cos x = -0.57`
(90 < x < 180)

`tan x = 0.82/-0.57 = -1.44`