# Suppose that y varies inversely with x. When x=14, then y=6. How do you find y when x=7?

${y}_{2} = 12$
$y = \frac{k}{x} \setminus \Rightarrow 6 = \frac{k}{14} \setminus \Rightarrow k = 6 \left(14\right) = 84$
$\setminus \therefore {y}_{2} = \frac{k}{7} \setminus \Rightarrow \frac{84}{7} = 12$