# Suppose #y# varies jointly as #x# and #z#. How do you find #y# when #x=6# and #z=8#, if #y=6# when #x# is 4 and #z# is 2?

##### 1 Answer

Aug 3, 2017

#### Answer:

#### Explanation:

If

#y = kxz#

where

In the situation, we're given that

#6 = k(4)(2)#

#k = 3/4#

Now that we know the proportionality constant (which stays the same), we can use it in solving for

#y = (3/4)(6)(8) = color(blue)(ulbar(|stackrel(" ")(" "36" ")|)#