# Suppose you roll two die. What is the probability of rolling a seven?

$\frac{6}{36} = \frac{1}{6}$

#### Explanation:

There are a total of 36 possible rolls on a set of 2 fair 6-sided dice:

$6 \times 6 = 36$

Out of that 36, how many can be a 7?

We can get a 7 with these roles:

$\left(1 , 6\right) , \left(2 , 5\right) , \left(3 , 4\right) , \left(4 , 3\right) , \left(5 , 2\right) , \left(6 , 1\right)$ - 6 ways

So the probability of rolling a 7 is:

$\frac{6}{36} = \frac{1}{6}$