The acceleration due to gravity on the moon is about one-sixth its value on earth. If a baseball reaches a height of 66 m when thrown upward by someone on the earth, what height would it reach when thrown in the same way on the surface of the moon?

1 Answer
Nov 21, 2016

I found: #396m#

Explanation:

We can use the relationship from kinemamatics:
#color(red)(v_f^2=v_i^2+2ad#
with:
#v_f=# final velocity which is zero at the top;
#v_i=# initial velocity (the same on Earth and on the Moon I suppose);
#a=# accelration of gravity (#=g# downwards);
#d=# distance (height in this case).

We have:

On Earth: #0=v_i^2-2g*66#
so that #v_i^2=2g*66#

On the Moon: #0=v_i^2-2/6gd#
so that: #v_i^2=2/6gd#

so considering the same values for #v_i^2# we can write:
#2cancel(g)*66=2/6cancelgd#
#d=6*66=396m#